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    Derivative Approximation

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    Approximate the derivative of y=x^3 at x=2 by assuming delta x = 0.001 and determining the corresponding change delta y. Compare the approximate value with the exact value.

    This is what I did - does it look at all right?

    delta y=8.120601-8=0.120601
    dy/dx~delta y/delta x = 0.120601/0.001=120.601

    © BrainMass Inc. brainmass.com March 4, 2021, 5:57 pm ad1c9bdddf

    Solution Preview

    dy/dx = 3x^2
    or dy = 3x^2 * dx
    dy = 3*2^2 * .001
    dy = .012 ( ...

    Solution Summary

    A derivative is approximated and compared to its exact value. The approximate value with the exact value is compared.