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Derivative Approximation

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Approximate the derivative of y=x^3 at x=2 by assuming delta x = 0.001 and determining the corresponding change delta y. Compare the approximate value with the exact value.

This is what I did - does it look at all right?

delta y=8.120601-8=0.120601
dy/dx~delta y/delta x = 0.120601/0.001=120.601

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Solution Summary

A derivative is approximated and compared to its exact value. The approximate value with the exact value is compared.

Solution Preview

dy/dx = 3x^2
or dy = 3x^2 * dx
dy = 3*2^2 * .001
dy = .012 ( ...

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