# Derivative Approximation

Not what you're looking for?

Approximate the derivative of y=x^3 at x=2 by assuming delta x = 0.001 and determining the corresponding change delta y. Compare the approximate value with the exact value.

This is what I did - does it look at all right?

y(2)=(2)^3=8

y(2.01)=(2.01)^3=8.120601

delta y=8.120601-8=0.120601

dy/dx~delta y/delta x = 0.120601/0.001=120.601

##### Purchase this Solution

##### Solution Summary

A derivative is approximated and compared to its exact value. The approximate value with the exact value is compared.

##### Solution Preview

dy/dx = 3x^2

or dy = 3x^2 * dx

dy = 3*2^2 * .001

dy = .012 ( ...

###### Education

- BE, Bangalore University, India
- MS, University of Wisconsin-Madison

###### Recent Feedback

- "Your explanation to the answers were very helpful."
- "What does 1 and 0 means in the repair column?"
- "Went through all of the formulas, excellent work! This really helped me!"
- "try others as well please"
- "Thank you, this helped a lot. I was not sure how to plug in those numbers to a formula. This was a great help. Now I have to figure out how to explain cost of capital is used in net present value analysis, and how cost of capital is used in net present value analysis. This stuff gets confusing."

##### Purchase this Solution

##### Free BrainMass Quizzes

##### Exponential Expressions

In this quiz, you will have a chance to practice basic terminology of exponential expressions and how to evaluate them.

##### Multiplying Complex Numbers

This is a short quiz to check your understanding of multiplication of complex numbers in rectangular form.

##### Graphs and Functions

This quiz helps you easily identify a function and test your understanding of ranges, domains , function inverses and transformations.

##### Solving quadratic inequalities

This quiz test you on how well you are familiar with solving quadratic inequalities.

##### Geometry - Real Life Application Problems

Understanding of how geometry applies to in real-world contexts