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    Complex and Real Solutions

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    Let A be a complex number and B a real number. Show that the equation
    |z|^2+Re(Az)+B=0 has a solution if and only if |A|^2 >= 4B. If this is so, show that the solutions set is a circle or a single point.

    © BrainMass Inc. brainmass.com March 4, 2021, 6:51 pm ad1c9bdddf
    https://brainmass.com/math/complex-analysis/complex-real-solutions-66199

    Solution Preview

    Proof:

    Since A is a complex number, we can suppose A=a+bi, where a,b are real numbers. B is a real number. We can also suppose z=x+iy, where x and y are real numbers.
    From the equation ...

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