solve the differential equation for springs
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A force of 64N stretches a spring 4 meters. The mass of 4kg is attached to the spring and set into motion in a medium that offer a damped force equal 16 times the velocity. If the mass is pulled down 2 centimeters from the equilibrium position and released. Find the equation for the position. Find the time(s) at which the mass passes the equilibrium position.
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The solution provides detailed explanation how to find out the differential equation for springs.
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