Mathematics - Applied Calculus - Logarithms and Exponents
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Solve for x finding the exact answer simplified
1b) 2 1n x - 1/3 1n x to the second power = 4
Solve for x (estimate valuses to the thousandths)
2a) 1n x = 5 - 1n 2x
2b) 5 = 7 - 3 e to the -2x power
3) f(x) = 2 + 6 / 1 + e to the kx power
3a) IF f(1)=4 find the value of k
3b) find f(2)
Applied Calculus 9th edition by Laurence D Hoffman and Gerald L. Bradley
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Solution Summary
The expert solves logarithms and exponents to different powers. A complete, neat and step-by-step solutions are provided.
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(1b) 2 ln x - (1/3) ln(x^2) = 4
2 ln x - (2/3) ln x = 4
(4/3) ln x = 4
ln x = 3
x = e^3
(2a) ln x = 5 - ln 2x
ln x + ln 2x = 5
ln(x * 2x) ...
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