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I am being asked to determine the type of quadrilateral defined by the point of intersection (using geometry & algebra) of the lines:

x - 4y + 3 = 0
5x - y - 8 = 0
x - 4y -16 = 0
6x - 5y - 1 = 0

##### Solution Summary

The type of quadrilateral is demonstrated.

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x - 4y + 3 = 0 --equation 1
5x - y - 8 = 0 --equation 2
x - 4y -16 = 0 --equation 3
6x - 5y - 1 = 0 --equation 4
Express all equation in terms of y. That would mean only y is found in the left side of the equation.

---------------------equation 1
x - 4y + 3 = 0
- 4y = -x -3
y = ...

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