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# Determine the Radius of Curvature

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For the composite bar indicated (see attachment), determine the radius of curvature caused by the couple of moment 70 Nm.

a) 9.16 mm

b) 12.73 mm

c) 11.87 mm

d) 10.41 mm

#### Solution Preview

Problem:

For the composite bar indicated (see attachment), determine the radius of curvature caused by the couple of moment 70 Nm.

a) 9.16 mm

b) 12.73 mm

c) 11.87 mm

d) 10.41 mm

Solution:

Let's denote:
- Est = the Young modulus of the Steel component
- EAL = the Young modulus of the Aluminum component
- Ist = the moment of inertia of the Steel cross section
- IAL = the moment of inertia of the Aluminum cross section

We will assume the following model:

The bending moment (M) can be decomposed in 2 components, each of them acting onto a single component of beam assembly, but in a such a way that the curvature of both deflected elements is the same:
...

#### Solution Summary

Radius of curvature caused by a couple moment on a composite bar is determined in a Word attachment.

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## Determine Electric Field & Calculate Speed of Electrons

Please see attached file. For 1st problem, I used the formula:
E1= Kq1/r2 = (8.99 x 10^9 NM/C^2)(-6.75 x 10^-6 C)/ (2.45 x 10^2 m)^2
E1= -10.109 x 10^7 N/C which = -1.01 x 10^8? Is this right?

I had to convert r to p(d)from 24.5cm into m (scientific notation) -
Not sure if I converted it correctly? 24.5 cm = 2.45 x 10^2 m?

Then, resolved each electric field into x and y components:
E1 (for x) = (-1.01 x 10^8 N/C)(cos22) = -0.936 x 10^8 N/C ?

E1 (for y) = (-1.01 x 10^8 N/C)(Sin22) = 0.378 x 10^8?
Added both x values together, then both y values, then used Pythagorean theorem to solve for magnitude of electric field.

Have I done this correctly? Or am I mixed up? Please check for me and if wrong, explain where I went wrong and why. Also, don't understand how to graph the table in question 2 or how to calculate the speed of the electrons from accelerating potential.Please explain-I'm lost at this pt.

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