Steady State Conditions

Related BrainMass Solutions

• Heat Equation, Boundary Conditions, Steady State Condition and Initial-Value Problem

  37233 Heat Equation, Boundary & Steady State Conditions, Initial Value Please help with the following problems involving numerical analysis.

• Current Through a Capacitor in Steady-State Conditions

  34804 Current Through a Capacitor in Steady State Conditions Determine the current through the capacitor just before and just after the switch is closed in the figure. Assume steady-state conditions for t<0.

• Steady State Solution

  Find a steady state solution of this equation. Use this knowledge to rewrite the solution u(x,t) of the initial-boundary value problem in the form u = v + w where w(x,t) has homogenous boundary conditions.

• The non-homogeneous heat equation

  Also since satisfies the boundary conditions, so is the steady state.   Converting a non-homogenous equation with time-independent forcing term to a homogenous equation.

• Non homogeneous 1D heat equation

  differential equation is (1.5) And the boundary conditions must still hold: (1.6) Integrating (1.5) twice we obtain: (1.7)   Applying boundary conditions we get the steady state solution

• Steady state diffusion through three layers system

  state concentration at the center and (1.27) So the solution for this system is: (1.28) The solution shows how to formulate the steady state equation, solve them and apply physical and mathematical conditions to obtain the concentration profile

• stable steady-state value

  307688 Stable Steady-State Value Solve the following linear, first-order differential equations and ensure that the initial conditions are satisfied. Show whether or not the steady-state solutions are stable. (a) 10y' = 5y and y(0) = 1.

• Laplace Transform Method and Control Systems

  state is y)t)_SS = 1/2.

• 1D heat equation

  (1.9) Is a solution to the original equation if (1.10) And (1.11) Now the boundary functions are constants (1.12) For the steady state we require and the boundary conditions still hold (1.13) This gives (1.14)