Just before the switch is opened at t=0, the current through the inductor is 1.70 mA in the direction shown in figure (PLEASE SEE ATTACHMENT). Did steady-state conditions exist just before the switch was opened?
L = 0.9 mH;
R1 = 6k Ohm;
R2 = 6k Ohm;
R3 = 3k Ohm;
Vs = 12V
If steady state exists the voltage drop across the inductor will be equal to 0 (v = L * di/dt with di/dt = 0 at steady state) and its resistance will be ...
This solution determines if an RL circuit is at steady-state.