Solving Input Impedance
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See attachment for the diagram.
Question: Determine how the input impedance Z (jw) = Vi (jw) / Ii (jw) behaves at extremely high or low frequencies.
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Solution Preview
This is an analysis circuit.
The Laplace transform of the elements is:
Resistor = R
Coil = s*L
Capacitor = 1/s*C
So:
R2 is in series with the coil so the resistance is R+Zcoil = 1100+j*w*0.19 = Zcoil,R2
This complex is parallel with the capacitor so:
1 1 1 ...
Solution Summary
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