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Solving Input Impedance

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See attachment for the diagram.

Question: Determine how the input impedance Z (jw) = Vi (jw) / Ii (jw) behaves at extremely high or low frequencies.

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This solution is comprised of a step by step response for understanding how to solve and work through this electrical circuit problem. All equations and variables are provided.

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This is an analysis circuit.

The Laplace transform of the elements is:
Resistor = R
Coil = s*L
Capacitor = 1/s*C

So:

R2 is in series with the coil so the resistance is R+Zcoil = 1100+j*w*0.19 = Zcoil,R2
This complex is parallel with the capacitor so:

1 1 1 ...

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