Homogeneous, Particular, and General Solutions
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Y''(t) + 6y'(t) + 13y(t) = te^(-t)
Compute the homogeneous solution yh(t).
Compute the particular solution yp(t).
Compute the general solution y(t) if y(0)=0 and y'(0)=1/8
https://brainmass.com/engineering/electrical-engineering/homogeneous-particular-general-solutions-25607
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Homogeneous Solution:
Aux. equation is: m^2 + 6m +13 = 0
m = (1/2)[-6 (+/-) sqrt(36-52) = -3 (+/-) i2
Two complex roots, m1 = -3+i2 and m2 = -3-i2
Hence, the homo. solution is:
yh(t) = e^(-3t) * [C1*Cos 2t + C2*Sin 2t]
Particular Solution:
Forcing function = te^(-t)
So, solution should ...
Solution Summary
The solution explains clearly and concisely the calculations necessary to reach the homogeneous, particular and general solutions of the given equation.
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