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Multiple senders CDMA

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Suppose that the receiver in figure (attached) wanted to receive the data being sent by sender 2. Show (by calculation) that the receiver is indeed able to recover sender 2's data from the aggregate channel signal by using sender 2's code.

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Solution Summary

The solution explains the technique to recover a sender's data from the received aggregate channel signal (vector) in words, mathematically and also with worked out examples for sender 2.

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Aggregate channel signal = Z = (0, -2, 0, 2, 0, 0, 2, 2, 2, 0, 2, 0, 2, -2, 0, 0)
Sender 2's code = C = (C1, C2, ....., C8) = (1, -1, 1, 1, 1, -1, 1, 1)

Size of sender 2's code vector = M = 8

To recover sender 2's data from the received aggregate channel signal (vector), receiver will take the dot product ...

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