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Titration: Calculating Percent Iron In Ore

A .823 g sample of an ore of iron is dissolved in acid and converted to Fe2> The sample is oxidized by 38.50 ml of 0.161 M ceric sulfate, Ce(SO4)2 soltion, The cerium 4 ion Ce4+ is reduced to Ce3+ Ion.
What is the percent iron in the ore?

Solution Preview

Moles of Ceric sulphate used = 0.0385*0.161 = 0.0061985 moles
Therefore, ...

Solution Summary

The solution is comprised of a concise step by step calculation to determine the percent iron in ore in a titration experiment.