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    Working with a radiactive material

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    The half life of Cl is 9.5 x 10(exponent 12)s. How many atoms of Cl are present in a sample with an activity of 1.5 x 10(exponent 9) atoms/s

    a. 2.1 x 10(exponent 22) atoms
    b. 6.3 x 10(exponent 3) atoms
    c. 4.9 x 10(exponent negative 23) atoms
    d. 1.4 x 10(exponent 22) atoms
    e. 7.0 x 10(exponent 23) atoms

    © BrainMass Inc. brainmass.com October 5, 2022, 3:03 pm ad1c9bdddf
    https://brainmass.com/chemistry/inorganic-chemistry/working-radioactive-material-7573

    SOLUTION This solution is FREE courtesy of BrainMass!

    Half life t_1/2 = 9.5 x 10^12 s

    means, in this time, the radioactive material will have reduced to half its original quantity.

    Given activity is A = 1.5 x 10^9 atoms/second

    WE WILL NOW FIND THE DECAY CONSTANT LAMDA (L)

    L = 0.693/t_1/2

    = 0.693/9.5 x 10^12 s = 0.073x10^-12 /Second

    Activity A = L N

    where N is the number of atoms

    Now N = A/L = 1.5 x 10^9/0.073x10^-12

    = 20.55 x 10^21

    approximately, the answer is 2.1 x 10^22 atoms

    Answer(A)

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    © BrainMass Inc. brainmass.com October 5, 2022, 3:03 pm ad1c9bdddf>
    https://brainmass.com/chemistry/inorganic-chemistry/working-radioactive-material-7573

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