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    zero order decomposistion of HI

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    For the zero order decomposistion of HI on a gold surface it takes 1.0 seconds for the concentration of HI to drop from 0.335M to 0.285M.
    HI(g)---> 1/2H2(g)+1/2I2

    I need to know what is the rate constant for the reaction, how long will it take for the concentration of a 0.650M solution to drop to 0.0100M, and what is the half life of a 0.400M solution

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    Solution Preview

    Zero order reactions are difficult because they seem too easy. The rate law is al follows.

    Rate = k

    In kinetics graphs, slope = -k...

    Since this is true find the rate, and you have ...

    Solution Summary

    The zero order decomposistion of HI is analyzed.