Weak Electrolyte undergoes Ionization
Water is a very weak electrolyte that undergoes the ionization-
H2O= H+(aq) + OH-(aq)
If k1= 2.4x 10-5 s-1 and k-1 = 1.3 x 10 to the eleventh/M*s
What is the equilibrium constant K where K= [H=] [OH-]/[H2O] ?
What is the product [H+][OH-] ?
What is [H+] ?
What is [OH-] ?
© BrainMass Inc. brainmass.com October 9, 2019, 8:02 pm ad1c9bdddfhttps://brainmass.com/chemistry/chemical-kinetics/weak-electrolyte-undergoes-ionization-137361
Solution Preview
H2O -------> H+(aq) + OH-(aq)
The rate of the forward reaction = k1[H2O]
The rate of the reverse reaction = k-1[H+][OH-]
At equilibrium, the two rates must be equal.
Therefore, at equilibrium:
k1[H2O] = k-1[H+][OH-]
Rearranging, we get:
k1/k-1 = [H+][OH-]/[H2O] = Kd
Kd is the ...
Solution Summary
This solution provides a detailed step by step solution to the given chemistry problem.
$2.19