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Weak Electrolyte undergoes Ionization

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Water is a very weak electrolyte that undergoes the ionization-

H2O= H+(aq) + OH-(aq)

If k1= 2.4x 10-5 s-1 and k-1 = 1.3 x 10 to the eleventh/M*s

What is the equilibrium constant K where K= [H=] [OH-]/[H2O] ?

What is the product [H+][OH-] ?

What is [H+] ?

What is [OH-] ?

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H2O -------> H+(aq) + OH-(aq)

The rate of the forward reaction = k1[H2O]

The rate of the reverse reaction = k-1[H+][OH-]

At equilibrium, the two rates must be equal.

Therefore, at equilibrium:

k1[H2O] = k-1[H+][OH-]

Rearranging, we get:

k1/k-1 = [H+][OH-]/[H2O] = Kd

Kd is the ...

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