Bessel and Legendre's Equations - Finding Lower Bound
The problem is to determine a lower bound for the radius of convergence for the two following equations. I am able to get p(x) and q(x) for both equations, but I'm confused on how to proceed. I would like to see the problem worked out and what the lower bound is.
Bessel's Equation:
Centered at 1
what I believe are p(x) and q(x)
p(x) = and q(x) =
Legendre's Equation
Centered at 0, and also try it centered at 1
© BrainMass Inc. brainmass.com December 24, 2021, 4:50 pm ad1c9bdddfhttps://brainmass.com/business/upper-and-lower-bounds-of-options/bessel-legendres-equations-lower-bound-10836
Solution Preview
Please see the attached doc file and please do not hesitate to contact me through the BrainMass staff if there is any vagueness. Good Luck.
We have:
and we want the lower bound for the radius of convergence about x=1. First we divide the equation by x^2:
now the radius is at least equal to the minimum between the radii of 1/x and (x^2-v)/x^2 about x=1:
1/x=1/(1+(x-1))=1-(x-1)+(x-1)^2-(x-1)^3+... provided |x-1|<1 therefore the radius of convergence about x=1 for the first one is 1.
(x^2-v)/x^2=1-v/x^2
we can ...
Solution Summary
The expert finds the lower bounds for Bessel and Legendre's equations.