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Equivalent annual cost method

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You are contemplating converting your car from burning gasoline to propane.

The following information is available:

Propane conversion kit (parts and labor) $750

Salvage value of kit after 5 years is $100
Kilometres travelled per year 40,000
Gasoline consumption 8 liters per 100 km.
Average gasoline price over 5 years is 0.40 cents per liter.
Annual maintenance advantage burning propane is $100
Propane is 10% cheaper and 10% more efficient.
The minimum attractive rate of return is 12%

Is the conversion justified economically?

Use equivalent annual cost method.

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Solution Preview

See attached Excel file.

Is the conversion justified economically?
Use equivalent annual cost method.

Conversion cost= $750
Salvage value (after 5 years)= $100

Gasoline cost per year= $1,280 =(40000/100)*8*0.4
Propane cost per year= $1,047 =(40000/(1.1*100))*8*0.4*0.9

Annual maintenance advantage= $100

Minimum attractive rate of return MARR= 12%

We first calculate the present value of costs. ...

Solution Summary

Uses equivalent annual cost method to evaluate the proposal to convert the car from burning gasoline to propane.

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Alternative and Equivalent Annual Cost Method

Can you help me get started with this assignment?

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The breeching on No. 2 boiler needs to be replaced because of severe corrosion.

Two alternatives are considered:

-replace with steel according to original specifications.

-replace with F.R.P.

You have obtained the following estimates:

Cost of breeching STEEL $15000
Cost of breeching F.R.P. $18000

Installation cost for STEEL $8000
Installation cost for F.R.P. $6000

Changes to steel supports for STEEL zero
Changes to steel supports for F.R.P. $3000

Life span of STEEL is 6 years
Life span of F.R.P. is 12 years

Annual maintenance for STEEL is $1200
Annual maintenance for F.R.P. is zero

Minimum attractive rate of return is 12%

Use equivalent annual cost method.

Which alternative would you select?

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