# chi-squared test

One-thousand individuals were screened for their genotype at the MN blood group locus. The numbers of each genotype were:

MM MN NN

298 489 213

Assuming random mating, calculate the gene frequency for the M allele and the expected genotype frequencies. Use the chi-squared test to determine that mating is random.

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#### Solution Preview

Hello,

You are given that the OBSERVED number of individuals with each genotype is as follows:

MM: 298 people

MN: 489 people

NN: 213 people

To determine the frequency of the M allele, you must divide the number of M alleles in the population by the total number of alleles in the population. Since there are 1000 individuals in the population and each individual has two alleles for their genotype, there are 1000*2 = 2000 total alleles in the population. The number of M alleles in the population is (2*298)+(489) = 1067 M alleles. Therefore, the frequency of the M allele is: 1067/2000 = 0.5335.

To determine the expected genotype frequencies, assuming random mating, you will use the Hardy-Weinberg equilibrium equation. Using "p" to represent the frequency of the M allele and "q" to represent the frequency ...

#### Solution Summary

This solution carefully calculates the gene frequency for the M allele and the expected genotype frequencies. It also applies the chi-squared test to determine that mating is random.