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Conditional Expectation Function

P(x1,x2)= (x1 choose x2) (1/2)^x1 (x1/15), x2= 0,1,2, ...., x1
x1= 1, 2, 3, 4 ,5

0 elsewhere
is the joint pmf of X1 and X2.

Determine E(X2|x1)

© BrainMass Inc. brainmass.com July 17, 2018, 4:10 am ad1c9bdddf

Solution Preview

The answer is x1/2

(See Attachment)

p(x1,x2)= (x1 choose x2) (1/2)^x1 (x1/15), x2= 0,1,2, ...., x1
...

Solution Summary

The conditional expectation functions are determined.

$2.19