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    Conditional Expectation Function

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    P(x1,x2)= (x1 choose x2) (1/2)^x1 (x1/15), x2= 0,1,2, ...., x1
    x1= 1, 2, 3, 4 ,5

    0 elsewhere
    is the joint pmf of X1 and X2.

    Determine E(X2|x1)

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    Solution Preview

    The answer is x1/2

    (See Attachment)

    p(x1,x2)= (x1 choose x2) (1/2)^x1 (x1/15), x2= 0,1,2, ...., x1

    Solution Summary

    The conditional expectation functions are determined.