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    Sampling Error when Estimating a Population Proportion

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    Assume the following data represents a population of 50 values. Values equal to 1 indicate that a particular attribute is present, a value equal to 0 indicates the attribute is not present.
    1......1......1......1......1......1......1......1......0......0
    0......1......1......0......0......1......1......1......0......1
    0......1......1......1......1......1......1......1......1......0
    1......1......1......1......1......1......1......0......1......1
    0......1......1......1......1......1......1......1......1......1

    a. Compute the population proportion.
    The population proportionate is the fraction of values in a population, which have a specific attribute. Population proportionate = X number of items having the attribute divided by N, the population size.

    b. A random sample of 15 items produced the following numbers: 1 1 1 0 0 1 0 0 1 1 0 0 0 1 0. Compute the sample proportion and the sampling error present in your sample.

    c. What is the range of extreme sampling error for a sample of 15 taken from this population?

    d. How would the range of extreme sampling error change if the sample size was set to 30? Discuss the advantages of having a larger sample size.

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    Assume the following data represent a population of 50 values. Values equal
    to 1 indicate that a particular attribute is present; a value equal to 0 indicates the attribute is not present.
    1 1 1 1 1 1 1 1 0 0
    0 1 1 0 0 1 1 1 0 1
    0 1 1 1 1 1 1 1 1 0
    1 1 1 1 1 1 1 0 1 1
    0 1 1 1 1 1 1 1 1 1

    a. Compute the population proportion.
    The population proportion is the fraction of values in a population, which have a specific attribute. Population proportionate = X number of items having the attribute divided by N, the population size.

    The attribute is present ...

    Solution Summary

    In this solution, questions about sampling error when estimating a population proportion are discussed within an attached Word document. All calculation details are provided along with explanations.

    $2.49

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