Sampling Distribution
Not what you're looking for?
35. The Democrat and Chronicle reported that 25% of the flights arriving at the San Diego airport during the first five months of 2001 were late (Democrat and Chronicle), July 23, 2001). Assume the population proportion is p = .25
A. Show the sampling distribution of _ , the proportion of late flights in a sample of1000flights
P
B. What is the probability that the sample proportion will be within .03 of the population proportion if a sample of size 1000 is selected?
C. Answer part (b) for a sample of 500 flights.
41. The mean television viewing time for Americans is 15 hours per week (Money, November 2003.) Suppose a sample of 60 Americans is taken to further investigates viewing habits.
Assume the population standard deviation for weekly viewing time is = 4 hours.
A. What is the probability the sample mean will be within 1 hour of the population mean?
B. What is the probability the sample mean will be within 45 minutes of the population mean?
Purchase this Solution
Solution Summary
The solution calculates the probability of finding a sample mean within a particular range from the population mean, probability of finding a sample proportion within a particular range from population proportion.
Solution Preview
Please see attached file for complete solution
The Democrat and Chronicle reported that 25% of the flights arriving at the San Diego airport during the first five months of 2001 were late (Democrat and Chronicle), July 23, 2001). Assume the population proportion is p = .25
A. Show the sampling distribution of P, the proportion of late flights in a sample of1000flights
population proportion=p= 25.00%
q=1-p= 75.00%
n=sample size= 1000
σp=standard error of proportion=√(pq/n)= 1.369% =√ ( 25.% * 75.% / 1000)
z=(proportion -population proportion)/σp= 1
Probability value corresponding to Z = 1 is 68.27% 0r 0.6827
proportion=mean proportion+zσp= 26.369% =0.25+(1*0.01369)
proportion=mean proportion-zσp= 23.631% =0.25-(1*0.01369)
Thus there is a 68.27% probability that the proportuion of flights are late is between 23.631% and 26.369%
z=(proportion -population proportion)/σp= 2
Probability value corresponding to Z = 2 is 95.45% 0r 0.9545
proportion=mean proportion+zσp= 27.738% =0.25+(2*0.01369)
proportion=mean proportion-zσp= 22.262% =0.25-(2*0.01369)
Thus there is a 95.45% probability that the proportuion of flights are late is between 22.262% and ...
Purchase this Solution
Free BrainMass Quizzes
Know Your Statistical Concepts
Each question is a choice-summary multiple choice question that presents you with a statistical concept and then 4 numbered statements. You must decide which (if any) of the numbered statements is/are true as they relate to the statistical concept.
Measures of Central Tendency
Tests knowledge of the three main measures of central tendency, including some simple calculation questions.
Terms and Definitions for Statistics
This quiz covers basic terms and definitions of statistics.
Measures of Central Tendency
This quiz evaluates the students understanding of the measures of central tendency seen in statistics. This quiz is specifically designed to incorporate the measures of central tendency as they relate to psychological research.