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Calculating the mean and standard error in the given cases

1. Find the mean of the sampling distribution of the sample size n = 36 if the population mean is 4 and the standard deviation is 3.
A. 4
B. 2
C. 1

2. Find the standard error of the sampling distribution of the sample size n = 36 if the population's mean is 4 and the standard deviation is 3.
A. 3
B. 1
C. 0.5

Question 3
Marks: 1 ACE Temp Service Company has found that the mean time required for a job applicant to take an aptitude test is 24.5 minutes with a standard deviation of 4.5 minutes. What is the mean of the sampling distribution of sample size 81?
A. 24.5
B. 12.25
C. 22

Question 4
ACE Temp Service Company has found that the mean time required for a job applicant to take an aptitude test is 24.5 minutes with a standard deviation of 4.5 minutes. What is the standard error of the sampling distribution of sample size 81?
A. 4.5
B. 9
C. 0.5

Question 5
A random sample of 81 files was randomly selected. What is the probability that the mean time applicants need for taking the test is greater than 25 minutes?
A. 0.3413
B. 0.1587
C. 0.4722

Question 6
Of the 2500 middle managers in a large company, 60% of them hold M.B.A. degrees. You select a random sample of 81 of them. What is the probability that the proportion in the sample with M.B.A. degrees is between 59.5% and 60.5%?
A. 0.0718
B. 0.0398
C. 0.1538

Solution Preview

1. Mean of the sampling distribution is the same as the population mean. So, the correct answer is A i.e. 4

2. Population standard deviation=3
Sample size=36
Standard error of sampling distribution=Population standard deviation/square root of sample size
=3/36^0.5
=0.5
Correct option is C i.e. ...

Solution Summary

Solutions to given problems explain the methodology to calculate the mean and standard error of sampling distribution in the given cases. Solutions are derived by using standard formulas.

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