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Statistics: Test freshmen and juniors for stressful events

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Reasearchers were interested in examining the number of stressful events experienced by college students. They collected data from 2 groups of students: freshmen and juniors. The instrument they used to collect the data was a simple checklist that asked the student to check every item that that has occurred to you in the last three months. There were 100 items sample terms such as I moved, I got married, someone close to me died, and I started a new job.

Freshmen data set: 8, 9, 10, 9, 10, 7, 8, 10, 10, 80

1. compute the mean
2. compute the median
4. compute the range
5. compute the standard deviation (you may use a spreadsheet if used include in your work)
6. what is the variance?
7. how would you describe this set of data? in other words how would you describe the average score (mean, median, or mode and why?) How would you describe the variability (range, standard deviation or both? Why?)

Junior data set: 3, 3, 3, 4, 3, 2, 4, 2, 3, 4

8. compute the mean
9. compute the median
10. what is the mode?
11. compute the range
12. compute the standard deviation. if spreadsheet is used must be included
13. what is the variance?
14. how would you describe this data? how would you describe the average score? (mean, median, or mode and why) how would you describe the variability (range, standard deviation or both and why?)
15. putting it all together: do freshmen and juniors report similar numbers of stressful events? How would you say the two groups compare?

Solution Summary

Test freshman and juniors for stressful events are analyzed.

Solution Preview

Your requested analysis and computations are given in the attached file.

First we compute the mean, median and mode number of stressful events experienced by freshmen.

Mean =

To find the median, we arrange the data in ascending order.

Ascending order = 7 , 8, 8, 9, 9, 10, 10, 10, 10, 80

Median =

The maximum number of scores reported are 10. Therefore, Mode = 10

Variance = = 505.2

Standard Deviation =

Range = 80 - 7 = 73

As the Mean of ...

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