Statistics: Simpson's Paradox
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Given:
P(A|B and C = .10, P(A|Not B and C) = .05
P(A|B and Not C) = .35, P(A|Not B and Not C) = .20
P(C|B) = .90, P(C|Not B) = .30
A = Promoted within last year
B = MBA Degree
C = Hired directly out of school
Can you derive probabilities: P(A|B) = .125, P(A|Not B) = .155
can you shed any light on this "Paradox"?
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Solution Summary
This solution contains step-by-step calculations to derive the probabilities of P(A|B) and P(A|Not B). It also illustrates Simpson's paradox in this relationship.
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