I know that each cruise (trip) is 1000 customers, with a standard deviation of 100. But how do I compute the percentages of cruises that take between 950 and 1025.
2. The five percent of cruises that represent the fewest number of passengers take on what number of passengers of less?
M = 1000
SD = 100
1. To compute the probability of having less than 1025 passengers, we need to find the z value by:
Z = (X-M)/SD = (1025-1000)/100 = 0.25
From a z-table, we ...
The solution examines standard deviation of cruise ship destinations.