# Probability of Coin Tosses using Probability Mass Function

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Consider a sequence of independent tosses of a coin. A head (H) or tail (T) is the result of the toss of a coin. P(H) = P(T) = .50.

X is the random variable

Let X be the number of tosses needed to get the first tail.

The p.m.f., probability mass function is given by P(X=x) = (1/2)^x, x = 1,2,...,

Calculate the probability that the first tail appears on an odd number of flips.

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##### Solution Summary

The probability of coin tosses using probability mass function is determined. The solution uses a random variable X.

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Since P(X = n) = (1/2)^n, n = 1, 2, ...

Now we only consider odd n's, that is P(X = ...

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