PROBLEM 4
Out of 11 people applying for an assembly job, 3 cannot do the work. Suppose two persons will be hired.
(a) How many distinct pairs are possible?
(b) In how many of the pairs will 0 or 1 people not be able to do the work?
(c) If two persons are chosen in a random manner, what is the probability that neither will be able to do the job?

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Solution.
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<br>(a) Since there are 11 people, there are C(11,2)=11*10/2!=55 distinct pairs are possible.
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<br>(b) We count them separately.
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<br> First, we ...

Solution Summary

PROBLEM 4
Out of 11 people applying for an assembly job, 3 cannot do the work. Suppose two persons will be hired.
(a) How many distinct pairs are possible?
(b) In how many of the pairs will 0 or 1 people not be able to do the work?
(c) If two persons are chosen in a random manner, what is the probability that neither will be able to do the job?

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Answer to 4 decimal places.

See attached graph for problem 3.
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Need some help on this, please show all work so I can save this for the future. I am very confused with accounting practices.
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