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    Poisson distribution probabilities and recursion relationship

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    The Poisson distribution is given by the following
    P(x,λ)=e ^ -λ * λ^x! x=0,1,2,3.....j.....
    Where λ>0 is a parameter which is the average value μ in poisson distribution.

    a) show that the maximum poisson probability P(x=j,λ) occurs at approximately the average value, that is λ=j if λ>1.
    (hint: you can take the first order derivative of the natural log of poisson probability, P(x=j, λ) with respect to λ and set it equal to 0

    b) show that when λ<1 the poisson probability is a monotonically decreasing function of j, i.e, P(0, λ)>P(1, λ)>P(2, λ)....P(j, λ).... And never has a maximum value
    (hint: you can use the recursion relationship of the poisson distribution to prove this statement)

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    https://brainmass.com/statistics/probability/poisson-distribution-probabilities-recursion-relationship-279724

    Solution Preview

    The Poisson distribution is given by the following
    P(x,λ)=e ^ -λ * λ^x/x! x=0,1,2,3.....j.....
    Where λ>0 is a parameter which is the average value μ in poisson distribution.
    a) show that the maximum poisson probability P(x=j,λ) occurs at approximately the average value, that is λ=j if ...

    Solution Summary

    Poisson distribution probabilities and recursion relationships are examined.

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