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Poisson Distribution, probabilities, 600 Bernoulli trials

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1. Suppose that X has a Poisson distibution with parameter "lambda" = 3
Find P(X>0)

2. Suppose you toss ten coins and count the number of heads. What is the probability that the number of heads you count will lie within two standard deviations of the mean?

3. Consider a sequence of 600 Bernoulli trials with a success probabiity of p=0.99. What is P(350 < X < 360)?

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Solution Summary

This solution helps explore the statistical concepts of Poisson distribution, probabilities and Bernoulli trials.

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(1) lambda = 3

P(x) = e^(-lambda) * (lambda^x) / x!

P(x > 0) = 1 - P(x = 0)

= 1 - [e^(-3) * (3^0) / 0!]

= 1 - e^(-3)

= 0.9502

(2) n = 10, p = 0.5, q = 1 - p = 0.5

SD = ...

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