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Normal Distribution

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The time needed to complete the final examination of MGSC 301 is normally distributed with a mean of 120 minutes and a standard deviation of 12 minutes.

a. What is the probability that a student will finish the examination in two hours or more?
b. What is the probability that a student will finish the examination in more than 100 minutes but less than 150 minutes?
c. What is the probability that a student will finish the examination in more than 140 minutes?

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Solution Summary

Calculates probability using Normal Distribution.

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The time needed to complete the final examination of MGSC 301 is normally distributed with a mean of 120 minutes and a standard deviation of 12 minutes.

a) What is the probability that a student will finish the examination in two hours or more?

Mean=2 hours = 120 minutes
Probability of exceeding mean = 50% as the normal distribution is symmetrical

Mean=M = 120 minutes
Standard deviation =s= 12 minutes
x= 120 minutes ...

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