Normal Distribution
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The time needed to complete the final examination of MGSC 301 is normally distributed with a mean of 120 minutes and a standard deviation of 12 minutes.
a. What is the probability that a student will finish the examination in two hours or more?
b. What is the probability that a student will finish the examination in more than 100 minutes but less than 150 minutes?
c. What is the probability that a student will finish the examination in more than 140 minutes?
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Solution Summary
Calculates probability using Normal Distribution.
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The time needed to complete the final examination of MGSC 301 is normally distributed with a mean of 120 minutes and a standard deviation of 12 minutes.
a) What is the probability that a student will finish the examination in two hours or more?
Mean=2 hours = 120 minutes
Probability of exceeding mean = 50% as the normal distribution is symmetrical
Mean=M = 120 minutes
Standard deviation =s= 12 minutes
x= 120 minutes ...
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