# Mean Household Size and Roulette Probability

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It's estimated that 57% of Americans live in households with 1 or 2 people, 32% live in households with 3 or 4 people and 11% live in households with 5 or more. Explain how you will find the expected number of people in an American household.

The probability of winning when you bet on a single number in roulette is 1 in 38. A $1 bet yields a net gain of $35 if it wins.

a. suppose that you bet $1 on the single number 23. What is your probability of winning?

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##### Solution Summary

This solution is provided in approximately 262 words in an attached .doc file. It uses calculations for the mean to find the solution to the number of people living in American households, and calculations probability of a roulette game.

###### Education

- BSc , Wuhan Univ. China
- MA, Shandong Univ.

###### Recent Feedback

- "Your solution, looks excellent. I recognize things from previous chapters. I have seen the standard deviation formula you used to get 5.154. I do understand the Central Limit Theorem needs the sample size (n) to be greater than 30, we have 100. I do understand the sample mean(s) of the population will follow a normal distribution, and that CLT states the sample mean of population is the population (mean), we have 143.74. But when and WHY do we use the standard deviation formula where you got 5.154. WHEN & Why use standard deviation of the sample mean. I don't understand, why don't we simply use the "100" I understand that standard deviation is the square root of variance. I do understand that the variance is the square of the differences of each sample data value minus the mean. But somehow, why not use 100, why use standard deviation of sample mean? Please help explain."
- "excellent work"
- "Thank you so much for all of your help!!! I will be posting another assignment. Please let me know (once posted), if the credits I'm offering is enough or you ! Thanks again!"
- "Thank you"
- "Thank you very much for your valuable time and assistance!"

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