For people with a certain disease, the length of time Y spent in remission is described by the following pdf

f(y) = (1/9)y^2, 0<=y<=3

where Y is measured in years.

What is the probability that a patient's remission lasts longer than 1 year?

Solution Preview

So, we have the pdf, (1/9) y^2, 0<=y<=3. To calculate probabilities from a pdf, we integrate. We are looking for the probability that remission lasts longer ...

Solution Summary

A step-by-step solution is provided in which it is demonstrated how to find probabilities. Attachment included.

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If x is normally distrubed with u = 20.0 and o = 4.0, determine the following:
a. P(x > 20.0)
b. P(16.0 < x < 24.0)
c. P(X < 12)
d. P(x = 22.0)
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f. P(x 15)

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(a) Calculate each probability (i-vi) and explain in words what it means.
i. P(S) ii. P(W) iii. P(S | W)
iv. P(S | B) v. P(S and W) vi. P(N and B)
Smoking by Race for Males Aged 18-24
Smoker

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1. P (x is greater than or equal to 13.5)
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a. Exactly 20 are cured.
b. All are cured.
c. No one is cured.
d. Twelve or fewer are cured.