# Binomial Probability Distribution

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Please help with the following problems.

The manager of the local Tim Horton's found that 60% of her employees call in sick on Fridays before the long weekend. Out of a sample of ten employees, what is the probability that:

A) exactly three employees will call in sick

B) not more than one employee will call in sick.

C) at least three employees will show up for work on Fridays before the long weekend.

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This posting helps with probability problems. In this problem, probability calculations are carried out using Binomial Probability Distribution.

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This is binomial distribution

p= probability that employee call in sick= 60%

q=1-p= probability that employee does not call in sick= 40%

A) exactly three employees will call in sick

Probability = (10 C 3)* p^3 q ^7=

(10 C 3)= 120

p^3= =60%^3

q^7= =40%^7

Thus

Probability = (10 C 3)* p^3 q ^7= 0.0425 = 4.25% Answer

B) not more than one employee will call in sick.

Probability that not more than one employee ...

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