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A certain airplane has two independent alternators to provide electrical power.

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Prepare answers to the following assignments from the e-text, Applied Statistics in Business and Economics, by Doane and Seward:

Chapter 5 - Chapter Exercises 5.62 and 5.70

Note: Methods of computation could include the usage of Excel, SPSS, Lotus, SAS, MINITAB, or by hand computation.

5.62

A certain airplane has two independent alternators to provide electrical power. The probability that a given alternator will fail on a 1- hour flight is .02. What is the probability that (a) both will fail? (b) Neither will fail? (c) One or the other will fail? Show all the steps

5.70

The probability is 1 in 4,000,000 that a single auto trip in the United States will result in a fatality. Over the lifetime, an average U.S. driver takes 50,000 trips. (a) What is the probability of a fatal accident over a lifetime? Explain your reasoning carefully. Hint: Assume independent events. Why might the assumption of independence be violated? (b) Why might a driver be tempted not to use a seat belt "just on this trip"?

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5.62

A certain airplane has two independent alternators to provide electrical power. The probability that a given alternator will fail on a 1- hour flight is .02. What is the probability that (a) both will fail? (b) Neither will fail? (c) One or the other will fail? Show all the steps

Solution.

Denote by E1 and E2 the events that alternators A and B will fail on a 1- hour flight, respectively. Then E1-bar and E2-bar denote the events that alternators A and B will NOT fail on a 1- hour flight, respectively. We know that E1 and E2 are independent, and P(E1)=P(E2)=0.02. So, P(E1-bar)=1-P(E1)=0.98; P(E2-bar)=1-P(E2)=0.98

(a) The probability that both will fail is equal to P(E1 and E2). Note that E1 and E2 are ...

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Recent Feedback
  • "Your solution, looks excellent. I recognize things from previous chapters. I have seen the standard deviation formula you used to get 5.154. I do understand the Central Limit Theorem needs the sample size (n) to be greater than 30, we have 100. I do understand the sample mean(s) of the population will follow a normal distribution, and that CLT states the sample mean of population is the population (mean), we have 143.74. But when and WHY do we use the standard deviation formula where you got 5.154. WHEN & Why use standard deviation of the sample mean. I don't understand, why don't we simply use the "100" I understand that standard deviation is the square root of variance. I do understand that the variance is the square of the differences of each sample data value minus the mean. But somehow, why not use 100, why use standard deviation of sample mean? Please help explain."
  • "excellent work"
  • "Thank you so much for all of your help!!! I will be posting another assignment. Please let me know (once posted), if the credits I'm offering is enough or you ! Thanks again!"
  • "Thank you"
  • "Thank you very much for your valuable time and assistance!"
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