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# T Test on Mean Difference and Computing R Squared

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t distribution, degrees of freedom= 21

Is the result sufficient to conclude that there is a significant difference in the ratings for two types of advertisements?

t-critical= ±______

t = ________

Compute r2 to measure the size of the treatment effect (round to three decimal places.)
write a sentence describing the outcome of the hypothesis test and the measure of effect size as it would appear in a research report.

Female participants (did not rate, rated) job recruitment materials with masculine-themed words significantly different than job recruitment materials with neutral words, (( t25)=1.205, t(25)=2.699, t(24)=2.588, t(24)=2.640) , (p<.05, t(25)=2.604, s=2.5, up=1.32) , (r=0.467, r2=0.095, r=0.315, r2=0.225).

suppose a researcher obtains a sample of n=16 adults who are between the ages of 65 and 75. the researcher uses a standardized test to measure cognitive performance for each individual. the participants then begin a 2 month program in which they receive daily doses of the blueberry supplement. at the end of the 2 month period the researcher again measures cognitive performance for each participant.
the results show an average increase in performance of MD= 7.4 with SS=1,215. does this result support the conclusion that the antioxidant supplement has a significant effect on cognitive performance? use a two tailed test with o=.05.
t distribution degrees of freedom=21

t-crtitical= ± _____
t= ________

the results indicate
*rejection of the null hypothesis, the antioxidant does not have a significant effect on cognitive performance
*failure to reject the null hypothesis, the antioxidant does not have a significant effect on cognitive performance
* failure to reject the null hypothesis, the antioxidant does have a significant effect on cognitive performance
*rejection of the null hypothesis, the antioxidant does have a significant effect on cognitive performance

construct a 5% confidence interval to estimate the average cognitive performant improvement for the population of older adults.
* 5.150-9.650
*5.150-7.400
*2.605-12.195
*7.400-12.195

https://brainmass.com/statistics/hypothesis-testing/test-mean-difference-computing-squared-585520

#### Solution Preview

Is the result sufficient to conclude that there is a significant difference in the ratings for two types of advertisements?
t-critical= ±2.064______
t = _1.32*sqrt(25)/sqrt[150/(25-1)]=2.64_______

compute r2 to measure the size of the treatment effect (round to three decimal places.)
r2=0.095

write a sentence describing the outcome of the hypothesis test and the measure of effect size as it would appear in a research ...

#### Solution Summary

The solution gives detailed steps on performing t test on mean difference, computing r square and confidence interval. Almost 150 words total, with calculations.

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