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Statistics: Mall Shoplifting and Commercial TV Stations

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1. The chief of security for the Mall of the Dakotas was directed to study the problem of missing goods. He selected a sample of 100 boxes that had been tampered with and ascertained that for 60 of the boxes, the missing pants, shoes, and so on were attributed to shoplifting. For 30 other boxes employees had stolen the goods, and for the remaining 10 boxes he blamed poor inventory control.

In his report to the mall management, can he say that shoplifting is twice as likely to be the cause of the loss as compared with either employee theft or poor inventory control and that employee theft and poor inventory control are equally likely? Use the .02 level.

2. In a particular market there are three commercial television stations, each with its own evening news program from 6:00 to 6:30 P.M. According to a report in this morning's local newspaper, a random sample of 150 viewers last night revealed 53 watched the news on WNAE (channel 5), 64 watched on WRRN (channel 11), and 33 on WSPD (channel 13). At the .05 significance level, is there a difference in the proportion of viewers watching the three channels?

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Solution Summary

The solution is comprised of a detailed step by step explanation for statistical word problems concerning mall shoplifting and commercial TV stations.

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1.
Test for proportion:
Ho: proportion of shoplifting (psl) = 2/3
H1: proportion of shoplifting (psl)  2/3

Standard error = (psl hypothesized*qsl hypothesized/n)^0.5 = ((2/3)*(1/3)/100)^0.5 = 0.0471
Z= (p observed - p hypothesized)/standard error = (0.6-2/3)/ 0.0471 = -1.415
This ...

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