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Mean amount of force necessary

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The quality control engineer for a furniture manufacturer is interested in the mean amount of force necessary to produce cracks in stressed oak furniture. She performs a twotail test of the null hypothesis that the mean for the stressed oak furniture is 650. The calculated value of the Z test statistic is a positive number that leads to a p-value of 0.080 for the test. True or False: Suppose the engineer had decided that the alternative hypothesis to test was that the mean was greater than 650. Then if the test is performed with a level of significance of 0.10, the null hypothesis would be rejected.

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This solution is comprised of a detailed explanation on rejecting or accepting the null hypothesis based on the P-value. Full description is given to support the answer.

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Since the two tailed P-value is 0.080 and Z test statistics is a positive number so if we want ...

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