Binomial Probability
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Q1).it is believed that 1 in every 10 cases are observed with diarrhoeal disease. To verify the claim, a sample of 10 persons is collected. A test is carried out at alpha=0.05.
a).state the underlying distribution of the problem.
b). find the probability that at least 7 persons carry the disease.
c). A test is conducted at alpha=0.05. suppose the null hypothesis is rejected if the result in b) is smaller than 0.05. what is the conclusion?
Q2). how to work out p-value?
if; t-test= -4.769, with df=7 therefore t7(0.95)= 1.895, since alpha is=0.05. Ho (null hypothesis) is rejected in t-test since -4.769 falls into the critical (rejection) region. where ( Ho: m=mo & H1: m not= mo)
is that; p-value= 2*P(T>=-4.769|T~t7)=1.998>0.05????
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Solution Summary
The solution provides step by step method for the calculation of binomial probability and p-value. Formula for the calculation and Interpretations of the results are also included.
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Hypothesis testing, test statistics-distributions, probability
Q1). It is believed that 1 in every 10 cases are observed with diarrhoeal disease. To verify the claim, a sample of 10 persons is collected. A test is carried out at alpha=0.05.
Answers
a). State the underlying distribution of the problem.
The underlying distribution is binomial with parameters n = 10 and p = 1/10 = 0.10
b). Find the probability that at least 7 persons carry the disease.
Let X be the number of persons carry diarrhoeal disease. Clearly X is binomial ...
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