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Computing Standard Error and Explaining T and Z Distribution

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Can you please help me with these questions? Some I have attempted to answer. Please let me know if they are right or wrong.

Find the estimated standard error for the sample mean for each of the following samples. (Use one decimal place)

n=4 with SS = 48
_______

n=6 with SS= 270
_________

n= 12 with SS= 132
________

Why do t distributions tend to be flatter and more spread out than the normal distribution is? The (denominator) (numerator) (product) I chose product??___ of the t statistic contains the (sample standard deviation)(population mean)(population standard deviation)__i chose sample standard deviation________, which is _(different)(unknown)(the same)__I chose different ?________for different samples. The z score uses the _(population standard deviation)(population size)(sample standard deviation)_i chose population standard deviation?______________which is __(the same)(different)(unknown)_i chose same?______for different samples, Therefore, the t statistic has __(greater)(equal)(less)___less?________variabilty.

use the distribution tool to find the t values that form the boundaries of the critical region for a two-tailed test with o= .05 for each of the following sample sizes. use three decimal places.
t distribution
degrees of freedom= 21

n=6
t= ±

n=12
t=±

n=24
t=±.

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Solution Summary

The solution gives detailed steps on computing standard error and explaining the difference between t and z distribution.

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Find the estimated standard error for the sample mean for each of the following samples. (use one decimal place)
n=4 with SS = 48
____standard error=sqrt(48/4)=_3.5__
n=6 ...

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