Purchase Solution

Finding the standard error of sample mean

Not what you're looking for?

Ask Custom Question

Question: Suppose N = 80000, n = 16000 and s = 50.
a. Compute the standard error of the sample mean using the finite population correction factor.
b. Repeat part a assuming n= 32000.
c. Repeat part a assuming n = 80000.
d. Compare parts a, b and c, and describe what happens to the standard error of the sample mean as n is increased.

Purchase this Solution
Solution Summary

Solution depicts the steps to estimate the standard error of sample mean. It also discusses the impact of change in sample size on standard error.

Solution provided by:
Lokesh Jain, MSc
Education
  • BEng (Hons) , Birla Institute of Technology and Science, India
  • MSc (Hons) , Birla Institute of Technology and Science, India
Recent Feedback
  • "Thank you"
  • "Really great step by step solution"
  • "I had tried another service before Brain Mass and they pale in comparison. This was perfect."
  • "Thanks Again! This is totally a great service!"
  • "Thank you so much for your help!"
Purchase this Solution
Free BrainMass Quizzes
Know Your Statistical Concepts

Each question is a choice-summary multiple choice question that presents you with a statistical concept and then 4 numbered statements. You must decide which (if any) of the numbered statements is/are true as they relate to the statistical concept.

Measures of Central Tendency

Tests knowledge of the three main measures of central tendency, including some simple calculation questions.

Measures of Central Tendency

This quiz evaluates the students understanding of the measures of central tendency seen in statistics. This quiz is specifically designed to incorporate the measures of central tendency as they relate to psychological research.

Terms and Definitions for Statistics

This quiz covers basic terms and definitions of statistics.

View More Free Quizzes
Related BrainMass Solutions

  • Findind Standard error of samples

    The standard deviation of the population is not known. a. A random sample of 50 households revealed a mean of $112,000 and a standard deviation of $40,000. What is the standard error of the mean? b.

  • Findind confidence interval for true mean

    Now let us calculate standard error of the mean We are given standard deviation Standard error = Sample mean = =14 Lower bound for confidence interval = Upper bound for confidence interval = We estimate mean of population will

  • A confidence interval of the mean

    Margin of error = 1.96(standard error) = (1.96)(.4) = .78 STEP 4 Add and subtract the margin of error from the sample mean to find the range of mean scores within which the population mean is expected, with 95%

  • Finding value of the sample test statistic

    =1.25 Here sample size is more than 30, we can use z-statistics Test statistics=Z(test)=(Sample mean-Hypothesized mean)/standard error=(62-60)/1.25=1.60 The solution depicts the methodology to calculate value of sample test statistic.

  • Estimation:Margin of error, Confidence interval, Sample Size

    Assume that the survey included 600 households and that the sample standard deviation was $175. a. With 95% confidence, determine the margin of error. b. Determine the 95% confidence interval estimate of the population mean c.

  • Finding the likelihood of samples with given means

    PLEASE SHOW ALL WORK IN EXCEL Complete the following: a A random sample of 50 households revealed a mean of $112,000 and a standard deviation of $40,000. What is the standard error of the mean?

  • Statistics - estimate of population mean, margin of error

    Finding Population Mean Estimate Finding 95.4% Margin of Error Given n = 40 , Sample Mean = 47 minutes , Standard Deviation = 5 minutes Population Mean Estimate = = ( 45.4505 , 48.5495 ) Approximate 95.4% error margin = 1.581138 For detailed

  • Finding Mean, Standard Error, and Probability of a Distribution

    504993 Finding Mean, Standard Error, and Probability of a Distribution 4. Assume that the population of heights of male college students is approximately normally distributed with mean m of 70.07 inches and standard deviation s of 6.48 inches.

  • Finding some probabilities

    b) If many samples of 64 were selected, what are mean and standard error of the mean (standard deviation of sample means) expected to be? What is expected to be the shape of the distribution of sample means?

  • Statistics: Margin of Error, Sample Sizes and Confidence Intervals

    Margin of error = 0.01, standard deviation = 0.25 Scenario: Researchers want to determine the mean number of hours students spend watching TV. A margin of error of 0.25 hour is desired.

View More Related Solutions