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# Class Boundaries of Datasets

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A data set that consist of 50 numbers has a minimum value of 16 and a maximum value of 74. determine the class boundaries using 2k>N rule if the data are
a) discrete
b) continuous

a) 16-25, 26-35, 36-45, 46-55, 56-65, 66-75
b) 16 to under 26, 26 to under 36, 36 to under 46, 46 to under 56, 56 to under 66, 66 to under 76.
(please show me how to get the answers the book offer solutions but I am not clear on the steps)

##### Solution Summary

The expert examines the class boundaries of data sets for minimum values.

##### Solution Preview

How many classes should we use? We use the 2^k>N rule. In this question, N=50, and we know that 2^5=32 and 2^6=64. So, we choose K=6. That means we need to set up 6 classes. As the maximum is 74 and minimum is 16, the range is 74-16=58. After we divide 58 by 6, we will ...

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###### Education
• BSc , Wuhan Univ. China
• MA, Shandong Univ.
###### Recent Feedback
• "Your solution, looks excellent. I recognize things from previous chapters. I have seen the standard deviation formula you used to get 5.154. I do understand the Central Limit Theorem needs the sample size (n) to be greater than 30, we have 100. I do understand the sample mean(s) of the population will follow a normal distribution, and that CLT states the sample mean of population is the population (mean), we have 143.74. But when and WHY do we use the standard deviation formula where you got 5.154. WHEN & Why use standard deviation of the sample mean. I don't understand, why don't we simply use the "100" I understand that standard deviation is the square root of variance. I do understand that the variance is the square of the differences of each sample data value minus the mean. But somehow, why not use 100, why use standard deviation of sample mean? Please help explain."
• "excellent work"
• "Thank you so much for all of your help!!! I will be posting another assignment. Please let me know (once posted), if the credits I'm offering is enough or you ! Thanks again!"
• "Thank you"
• "Thank you very much for your valuable time and assistance!"

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