Share
Explore BrainMass

# Statistics - Linear Programming Problem

The company I work for makes stainless steel surgical bars and bronze pipe. Each pound of stainless steel surgical bar takes approximately .25 hours of labor and uses roughly 5 kilowatts of electricity. Each pound of bronze pipe takes approximately .5 hours of labor and uses roughly 2 kilowatts of electricity. In creating the bronze pipe, we discover that production is limited by the fact that we can only get about 60 lbs of raw material per each workday. Due also to other electric needs, our electricity is also limited. Our limit for usage is 500 kilowatts per day and our production labor is limited to 40 person-hours/day.

Now in knowing all of this, our company has determined that the profit from stainless steel surgical bars is \$.25 per pound and the profit we make from bronze pipe is \$.40 per pound. How much of each should be produced to maximize profit and what is the maximum profit?

x = number of pounds of stainless steel surgical bars
y = number of pounds of bronze bars
Maximize P = \$.25x + \$.40y
Constraints:
y &#8804; 60
5x + 2y &#8804;500
.25x + .5y &#8804; 40
x &#8805; 0
y &#8805; 0

*This is an example I am working on but I cannot seem to figure out the full solution or how to graph it. I am stuck on this example and could use some help in figuring out the graph as well.

#### Solution Preview

The solution file is attached.

The company I work for makes stainless steel surgical bars and bronze pipe. Each pound of stainless steel surgical bar takes approximately .25 hours of labor and uses roughly 5 kilowatts of electricity. Each pound of bronze pipe takes approximately .5 hours of labor and uses roughly 2 kilowatts of electricity. In creating the bronze pipe, ...

#### Solution Summary

Linear programming problems in statistics is determined. A Complete, Neat and Step-by-step Solution is provided in the attached file.

\$2.19