When 500 college students are randomly selected and surveyed, it is found that 135 of them own personal computers (based on data from the America Passage Media Corporation).
A. Find the point estimate of the true proportion of all college students who own personal computers.
B. Find a 95% confidence interval for the true proportion of all college students who own personal computers.
n = 500
(A) p = 135/500 = 0.27
(B) q = 1 - p = 1 - 0.27 = ...
Neat and step-by-step solutions are provided.