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Overdue Promotion Hypothesis Testing

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Part 1:
A study was conducted to see if more than 60% of the American corporate work force felt that they were overdue for a promotion. A random sample of 1500 Americans currently working in a corporate atmosphere was taken. 855 said that they did feel that a promotion was overdue.

A 95% confidence interval for estimating the true percentage of the population that felt this way would have a margin of error to be?

Part 2:
Using the same info in italics, to reduce the margin of error to 2% and increase the confidence level to 99%, how many workers should be sample in a future study?
(for p* use the results from the sample)

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Solution Summary

This solution calculates the margin of error of the study on overdue promotions in the corporate workforce and also when the margin of error is reduced to 2%. All steps and formulas are shown in a structured manner.

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Question 3 (2 Parts):

Part 1:

A study was conducted to see if more than 60% of the American corporate work force felt that they were overdue for a promotion. A random sample of 1500 Americans currently working in a corporate atmosphere was taken. 855 said that they did feel ...

Solution provided by:
Changping Wang, MA
Education
  • BSc , Wuhan Univ. China
  • MA, Shandong Univ.
Recent Feedback
  • "Your solution, looks excellent. I recognize things from previous chapters. I have seen the standard deviation formula you used to get 5.154. I do understand the Central Limit Theorem needs the sample size (n) to be greater than 30, we have 100. I do understand the sample mean(s) of the population will follow a normal distribution, and that CLT states the sample mean of population is the population (mean), we have 143.74. But when and WHY do we use the standard deviation formula where you got 5.154. WHEN & Why use standard deviation of the sample mean. I don't understand, why don't we simply use the "100" I understand that standard deviation is the square root of variance. I do understand that the variance is the square of the differences of each sample data value minus the mean. But somehow, why not use 100, why use standard deviation of sample mean? Please help explain."
  • "excellent work"
  • "Thank you so much for all of your help!!! I will be posting another assignment. Please let me know (once posted), if the credits I'm offering is enough or you ! Thanks again!"
  • "Thank you"
  • "Thank you very much for your valuable time and assistance!"
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