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find the width for the confidence intervals

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The owner of Limp Pines Resort wanted to know the average age of its clients. A random sample of 25 tourists is taken. It shows a mean age of 46 years with a standard deviation of 5 years. The width of a 98 percent CI for the true mean client age is approximately ____ years. In a sample size calculation for a mean, if the confidence level decreases, the size of the sample needed will increase.

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The solution provides detailed explanation how to find the width for the confidence interval.

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The critical value for 98 confidence interval is 2.33.
Width of 98 confidence interval is 2*critical value*standard ...

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