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    Confidence and prediction intervals

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    Obtain a 95% CI for o^2.

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    a) for the sample, N = 20 and df = 19
    then the two tailed 90% t value with df 19 is t = 1.729
    the mean = (19.170 + 21.138) / 2 = 20.154
    then standard error is
    SE = (21.138 - 20.154) /1.729 = 0.569
    So the sample variance is S squared = n*SE^2 = 20*0.569^2 = 6.475

    Use the X2 (chi-squared) distribution for the confidence interval for the ...

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    This solution shows how to obtain confidence and prediction intervals.

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