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Confidence interval for the difference in mean scores

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An investigator at a nearby university wants to find out from a recent "math skills" test if there is any difference in scores
between full-time and part-time students. Records show the following:

Student Mean Score Standard Deviation Number

Full-Time 83 12 45
Part-Time 70 15 55

Compute a 95% confidence interval for the difference in mean scores

Please see the attached file for full problem description.

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Solution Summary

Computes a 95% confidence interval for the difference in mean scores of full-time and part-time students.

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Please see thae attached file for the answer.

sx1-x2=standard error of the difference between two means=square root of (s1^2/n1 + s2^2/n2)= 2.7002
=square root of (12 ...

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