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Confidence interval for proportion

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A survey of 4,581 U.S. households that owned a mobile phone found that 58 percent are satisfied with the coverage of their cellular phone provider.

Assuming that this was a random sample, construct a 90 percent confidence interval for the true proportion of satisfied U.S. mobile phone owners. (Round intermediate calculations to 4 decimal places. Round your answers to 3 decimal places.)

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Solution Summary

Step by step method for computing Confidence interval for proportion is given in the answer.

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