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Confidence interval estimation

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The security department of a state university is planning its budget for the next year. In estimating the man-hours for security during university sponsored music concerts, the average length of music concerts is needed. A random sample from thirty-six security departments at universities was taken and the sample mean length of concerts was 160 minutes. Suppose the population standard deviation is 45 minutes. A 95 percent confidence interval for the true mean duration of music concerts is
for this one I came up with 2 solutions 147.63 to 172.37 and when doing it over to check i got 145.3 to 174.7

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The solution provides step by step method for the calculation of confidence interval . Formula for the calculation and Interpretations of the results are also included.

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Confidence interval
The security department of a state university is planning its budget for the next year. In estimating the man-hours for security during university sponsored music concerts, the average length of music concerts is needed. A random sample ...

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