a. What percent of the students scored below 320?
b. What percent of the students scored between 400 and 525?
c. Twenty percent of the students had a test score above what score?
Let X represent the score of the college entrance test. From the condition, the mean of X is m=500, the standard deviation of X is d=75. X satisfies the normal distribution. So we can set Y=(X-m)/d=(X-500)/75, then Y ...
Solution provides detailed response to three questions regarding standard deviation of a college entrance test.