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A man standing on a bridge 30m above the water throws a stone in a horizontal direction. Knowing that the stone hits the water 40m from a point on the water directly below the man determine (a)the initial velocity of the stone (b)the distance at which the stone would hit the water if it were thrown with the same velocity from a bridge 10m lower.

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The solution gives all steps along with proper explanations so that you can solve similar problems yourself. All mathematical steps are clearly shown.

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When the stone touches the water below, the potential energy of the stone when the man released the stone gets converted to kinetic energy.

Thus we can write, m g h = (1/2) m v^2 ...

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